2x^2-8x+5x=2x-3

Solution for 2x^2-8x+5x=2x-3 equation:

2x^2-8x+5x=2x-3

We move all terms to the left:

2x^2-8x+5x-(2x-3)=0

We add all the numbers together, and all the variables

2x^2-3x-(2x-3)=0

We get rid of parentheses

2x^2-3x-2x+3=0

We add all the numbers together, and all the variables

2x^2-5x+3=0

a = 2; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·2·3
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-1}{2*2}=\frac{4}{4}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+1}{2*2}=\frac{6}{4}
=1+1/2
$